-55y^2+25y+50=0

Solution for -55y^2+25y+50=0 equation:

-55y^2+25y+50=0

a = -55; b = 25; c = +50;
Δ = b2-4ac
Δ = 252-4·(-55)·50
Δ = 11625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11625}=\sqrt{25*465}=\sqrt{25}*\sqrt{465}=5\sqrt{465}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{465}}{2*-55}=\frac{-25-5\sqrt{465}}{-110}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{465}}{2*-55}=\frac{-25+5\sqrt{465}}{-110}
$